Final Exam and Project Schedule

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WSU ARCH 463/563 ...

 ... your final exam will be emailed shortly (next hour or so).  It is `required', and `take-home' format.  It is due by 5 pm Thursday, 12/15 to my Faculty Mailbox on 5th Floor Carpenter Hall. 

The Graduate Projects (Deck Construction Documents) are also due at that time.

I STRONGLY recommend you keep personal copies of both.


UI ARCH 462 ...

Concrete Beam Test Reports are due 5 pm, Tuesday, 12/13, to my Faculty Mailbox in the Architecture Faculty Office/Mailroom (Sandi's office). 



BOTH CLASSES:  I will be somewhat available by appointment in Moscow during the week if you have any last minute questions, struggles, etc.

Example Experimental Beam Calcs - PREDICTED PERFORMANCE

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Yeah, a couple are blurred.  Get over it.

Pretty Retaining Wall ...

Gosh this is a pretty wall ...

 ... looks like it has some batter.  Gravel backfill, probably reinforced backfill zone.  Gravel provides some surface stability, a `path' if needed, to above, and is a better backfill material overall (less lateral pressure, better drainage). 

The blocks also accommodate the changing longitudinal grade.  The pavement at toe helps keep the wall from sliding.

Sweet.

Assn 3 Problem 1 Page 1 ... FIXED

 ... so, yeah, I started with the wrong `d' ... but all it gave me was a wrong rho, and slightly wrong [          ].   Note that I took the easy way out and still calculated strength even though the reinforcement ratio was less than min.  But the first guess was to see how we were coming in strength-wise anyway.

Assignment 3 prob 2 (WSU 463/563)

 ... here is the solution to # 2 of assignment 3.

Note that the 18 in. max spacing governs over the 0.0033 min. reinf ratio, and the 0.0033 ratio governs over strength.

 ... hmmmm ... we could have just started with # 5 at 18 in. o.c. and found that it was both strong enuf and met the min. rho.

UPDATE:  WHOA! ... we need to check c) ...

From Table 9.5(a) ... the min. depth of the member needs to be L/20 ...

So, L/20 = 10 x 12 in. / 20 = 6 in.

Since our slab is 6 in. thick. ... YAY! ... we are deemed good without having to do detailed deflection calcs.

Doc

Assn 3 Prob 1 (WSU 463 / 563) - FIXED???!!!

 ... here! 


SOME STUFF DELETED, SOME REPEATED (FROM THE DELETED!


LOAD …


sigma top = 0 x 100 = 0 psf

sigma bot = 8 x 100 = 800 psf

sigma ave = 400 psf


Whole force `W’ on wall = 400 psf x 8 ft tall x 1 ft of wall width = 3200 lb.


Moment resulting from W (triangular load) = 0.1283 W L = 3285 lb-ft … (from reference materials, triangular distributed load, etc., blah, blah)

Mu = 1.6 M = 1.6 x 3285 lb-ft = 5255 lb-ft



STRENGTH

… try # 3 @ 4 in. o.c.

Doc

Assignment 3, posted with some more comments (notes) ...

here: http://www.woodengineering.com/edu/wsu/463-563/463-563-assn-3.html

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